click below
click below
Normal Size Small Size show me how
Parabolas
Determing the Equation of parabola
| Question | Answer |
|---|---|
| y=a(x-h)²+k | vertex form |
| y=a(x-h)²+k vertex | (h,k) |
| y=a(x-h)²+k axis of symmetry | x=h |
| ax²+bx+c | standard form |
| ax²+bx+c axis of symmetry | -b/2a |
| ax²+bx+c y-intercept | c |
| a(x-p)(x-q) | intercept form |
| a(x-p)(x-q) x-intercepts | (p,0) (q,0) |
| a(x-p)(x-q) axis of symmetry is halfway between _________ | p and q |
| a(x-p)(x-q) x coordinate of vertex | p+q/2 |
| ax²+bx+c x coordinate of vertex | -b/2a |
| Form of Equation y=... | y=a(x-h)^2+k |
| Form of Equation x=... | x=a(y-k)^2+h |
| opening up, y=... | a>0 |
| opening down, y=... | a<0 |
| opening to the right x=... | a>0 |
| opening to the left x=... | a<0 |