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Org Chem Ch.18

Reactions of Aromatic Compounds

QuestionAnswer
What is a characteristic reaction of benzene? electrophilic aromatic substitution (hydrogen is replaced by an electrophile)
since benzene is especially stable, what reactions are favored? reactions that maintain the aromatic ring
Regardless of electrophile E+ used, all electrophilic aromatic substitution reactions occur by the same _#_-step mechanism two-step
What is the general two-step mechanisms of substitution? (1) addition of E+ to form a resonance-stabilized carbocation (2) deprotonation with base
Which step is the rate-determining step? step [1] addition of E+ is the rate-determining step as its transition state is at higher energy
Halogenation of benzene occurs with only two halogens: Cl2 (in presence of FeCl3) or Br2 (in presence of FeBr3)
Halogenation of Benzene: Step [1] X2 reacts with FeX3 to generate an electrophile (XX+ -FeBr3)
Halogenation of Benzene: Step [2] Addition of the electrophile to form a carbocation (pi bond attacks electrophile and FeX4- is formed)
Halogenation of Benzene: Step [3] Loss of proton to reform aromatic ring (FeX4- takes proton and pi bond reforms on ring)
nitration (NO2) and sulfonation (SO3H) of benzene requires what? a strong acid (H2SO4)
formation of the the electrophile (+NO2) for nitration formed by the protonation of HNO3, followed by the loss of water (HNO3 + H2SO4)
formation of the electrophile (+SO3H) for sulfonation formed by the protonation of SO3 (SO3 + H2SO4)
Friedel-Crafts Alkylation Treatment of benzene with an alkyl halide and a Lewis Acid (AlCl3) forms an alkyl benzene
Friedel-Crafts Acylation treatment of benzene with an acid chloride (RCOCl) and AlCl3 to form a ketone (O=C-R)
In order to be reactive in Friedel-Crafts alkylation, a halide must be bonded to a sp3 C. What kind of halides DO NOT react in a Friedel-Crafts alkylation? vinyl halide and aryl halide (halide bonded to sp2 C)
The Friedel-Crafts reaction can yield products having rearranged carbon skeletons when __ or __ alkyl halides are used as starting material 1 or 2
What does this rearrangement do? converts a less stable 1 or 2 carbocation to a more stable 3 carbocation
what is 'rearranging'? the positive charge can trade spots with an H (with its bond attached)
Other functional groups that form ________ can also be used as starting material carbocation
give two examples of other functions groups forming a carbocation that could be used as an electrophile in Friedel-Crafts alkylation protonation of an alkene forms a carbocation. and the protonation of an alcohol, followed by the loss of water forms a carbocation (both use H2SO4)
starting materials that contain both a benzene ring and an electrophile are capable of what? intramolecular Friedel-Crafts reactions
Many substituted benzene rings undergo electrophilic aromatic substitution. Each substituent can effect the _______ _______ in the benzene ring electron density (increase or decrease)
_________ of electron density to the ring makes benzene more electron rich donation
_________ of electron density from the ring makes benzene less electron rich withdrawal
what makes a substituent on a benzene ring electron donating or electron withdrawing? inductive effects and resonance effects
Inductive effects stem from the ____________ of the atoms in the substituent and the _________ of the substituent group electronegativity, polarizability
atoms more electronegative than carbon (N, O, X) exhibit an electron-_________ inductive effect withdrawing
polarizable alkyl groups donate electron density and exhibit an electron-__________ inductive effect donating
resonance effects can either donate or withdraw electron density, depending on what? whether they place a (+) or (-) charge on the benzene ring
a resonance effect is electron-_________ when resonance structures place a negative charge on the carbons of benzene donating
a resonance effect is electron-_________ when resonance structures place a positive charge on the carbons of benzene withdrawing
General electron-donating groups R groups and Z groups (N or O)
General electron-withdrawing groups X (halogens) and Y (atom bearing full or partial + charge)
a substituent effects two aspects of the electrophilic aromatic substitution reaction rate of reaction and orientation
Ortho, Para Directors are ________ activators (activate a benzene ring)
What is the general structure of ortho,para directors? R Group or Z: Group (not halogen)
rank ortho, para directors in order of increasing activation R < :NHCOR < OR < OH < NH2, NHR, NR2
ortho,para directors have electron-_________ groups that activates the benzene ring to electrophilic attack donating
Meta Directors are ___________ deactivators (deactivate a benzene ring)
What is the general structure of meta directors? Y (full or partial + charge)
rank meta directors in order of increase DEactivation +NR2 < NO2 < SO3H < CN < COOH < COOR < COR < CHO
meta directors have electron-________ groups that deactivate the benzene ring to electrophilic attack withdrawing
Halogens are in a group by themselves. What do halogens do to benzene ring? they deactivate a benzene ring and direct substitution ortho and para
_________ react faster than benzene while __________ react more slowly than benzene activators, deactivators
To understand why some substituents make a benzene ring react faster or slower, we must evaluate the rate-determining step of the mechanism. What is the rate-determining step of electrophilic aromatic substitution? the first step: addition of the electrophile to form a resonance-stabilized carbocation
the more stable the carbocation, the _______ the reaction faster (lower in energy the transition state)
electron-donating groups _______ the carbocation and activate a benzene ring towards electrophilic attack stabilize
electron-withdrawing groups _______ the carbocation and edactivate a benzene ring towards electrophilic attack destabilize
to determine the directing effects of a given substituent, we can use a stepwise procedure: (1)draw all resonance structures for the carbocation formed from E+ attack (o,m, and p) (2) evaluate the stability of the intermediate resonance structures. E+ attacks at those positions that give most stable carbocation
Benzene rings activated by strong electron-donating groups (OH, NH2) and their derivatives (OR, NHR, and NR2) undergo __________ when treated with X2 and FeX3 polyhalogenation (every ortho and para H is replaced)
monosubstitution of H by X occurs with X2 ALONE without added catalyst. This forms what in the products? a mixture of ortho and para products
Reinforcing Directing Effects: When the directing effects of two groups reinforce, the new substituent is located where? on the position directed by both groups
Opposing Directing Effects: When the directing effects of two groups oppose each other, then what? the more powerful activator wins
No substitution occurs between two meta substituents because of _________ crowding
nucleophilic aromatic substitution results in what? the substitution of a halogen on a benzene ring by a nucleophile
What two different mechanisms are proposed to explain the results of the reaction? addition-elimination or elimination-addition
nucleophilic substitution by addition-elimination mechanism (e-withdrawing groups at o and p positions are required) (1)addition of nucleophile to form a carbanion (2) loss of the leaving group to reform the aromatic ring
Reactivity trends in nucleophilic aromatic subst.: increasing the number of e-withdrawing groups _______ the reactivity of the aryl halide increases (e-withdrawing groups stabilize the intermediate carbanion)
Reactivity trends in nucleophilic aromatic subst.: increasing electronegativity of the halogen ___________ the reactivity of the aryl halide increases (stabilizes carbanion by inductive effect
Nucleophilic Aromatic Subst. by elimination-addition: (1)elimination of HX to form benzyne (2) nucleophilic addition to form subst. product
Nucleophilic aromatic substitution by an elimination-addition mechanism affords substitution on the carbon directly bonded to the leaving group and the carbon adjacent to it. Explain position of product p and m
Created by: cmccartney2
 

 



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