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GCSE Acceleratio
GCSE Acceleration
Question | Answer |
---|---|
What does a horizontal line represent on a velocity-time graph? (describe the motion) | Constant speed |
What does a diagonal straight line up shows on a velocity-time graph? (describe the motion) | The object is accelerating |
What does a diagonal straight line down shows on a velocity-time graph? (describe the motion) | The object is decelerating |
How would you show an object at rest in a velocity-time graph? | A horizontal line ON THE X-AXIS |
CHALLENGE: What does a diagonal straight line down, UNDER THE X-AXIS shows on a velocity-time graph? (describe the motion) | The object is MOVING BACKWARDS AND ACCelerating |
CHALLENGE: What does a diagonal straight line up UNDER THE X-AXIS shows on a velocity-time graph? (describe the motion) | The object is MOVING BACKWARDS AND DECelerating |
How would you show that an object is accelerating on a vt graph? | Straight line diagonally going up |
How would you show that an object is decelerating on a vt graph? | Straight line going diagonally down |
How would you work out the acceleration using a vt graph? | Divide the RISE on y-axis by the RISE in x-axis |
How do you work out the distance using a vt graph? | Work out the area under the graph (remember that the area of a triangle is height x width/2) |
What is the acceleration of a car moving from rest position to 30m/s in 20secs? | a=v/t=(30-0)/20=1.5 m/s^2; remember it is the RISE in velocity and the RISE in time |
What distance would be covered if a car slowed down from 30m/s to 20m/s in 20s? | area of the rectangle: 20 m/s x 20s= 400m; area of the triangle: 10m/s x 20s /2=100m; total=500m |
What is the deceleration of a car moving from 30m/s to 20m/s in 20secs? | a=v/t=(20-30)/20=MINUS 1 m/s^2; remember it is the RISE in velocity and the RISE in time; and DECELERATION is negative |
What is the weight of a 70kg man? | 700N |
What is the weight of a 60kg woman on the Moon (gravity is 6 times less than on Earth) | On Earth 600N; On the Moon, 60N |