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Units, Moles, Calcs
A set of cards to revise mole calculations
| Question | Answer |
|---|---|
| g | amount in grammes |
| mol | amount in moles |
| dm3 | amount in cubic decimetres |
| cm3 | amount in cubic centimetres |
| 24dm3 | molar volume of any gas |
| convert 24dm3 to cm3 | 24 000cm3 |
| 6.02 x 10E23 | 1 mole of anything |
| Convert 25cm3 to dm3 | 0.025dm3 |
| Convert 24dm3 to cm3 | 24 000cm3 |
| g/dm3 | concentration in grammes per cubic decimetre |
| gdm-3 | concentration in grammes per cubic decimetre |
| mol/dm3 | mol/dm3 |
| moldm-3 | moldm-3 |
| mol | amount in moles |
| Number of atoms in 2 moles of Neon (Ne) | 1.20x10E24 |
| Number of atoms in 1 moles of chlorine (Cl2) | 1.2010E24 |
| Number of molecules in 1 mole of chlorine (Cl2) | 6.0210E23 |
| 24 000cm3 | Molar volume of any gas |
| Number of molecules in 48g of oxygen gas | 9.05E23 |
| Number of moles of NaOH in 25cm3 of a 0.1M solution | 0.0025 |
| Mass of NaOH in 25cm3 of a 0.1M solution (2 formula triangles needed) | 0.1g |
| Mass of NaOH in 1dm3 of a 0.1M solution (2 formula triangles needed) | 4g |
| Equation for the reaction of sodium hydroxide (NaOH) and sulphuric acid H2SO4 | 2NaOH + H2SO4 = Na2SO4 + 2H2O |
| Number of moles of sulphuric acid which will react with 0.1 moles of sodium hydroxide 2NaOH + H2SO4 = Na2SO4 + 2H2O | 0.05 |
| Number of moles of sulphuric acid (H2SO4) in 12.55cm3 of a 0.1M solution | 0.001255 |
| Mass of sulphuric acid (H2SO4) in 12.55cm3 of a 0.1M solution | 0.12299 |
| Number of moles of oxygen gas in 12 000cm3 | 0.5 |
| Mass of oxygen gas in 12 000cm3 | 16g |
Created by:
willocka
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