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# module 17

solve by using quadratic formula x^2+3x+2=0 x= 1 or x= -2
solve by using quadratic formula (x+3)(x+2)=2 x= -1 or x= - 4
How many solution(s) will a negative discriminant have? two complex but not real solutions
If the discriminant is positive how many solution(s) will it have? two real solutions
If the discriminant is zero how many solutions will it have? one real solution
a=1 b=3 c=4 use a, b, and c to find the discriminant then determine how many solution(s) it will have -13, negative= two complex but not real solutions
a=2 b=20 c=1 use a, b, and c to find the discriminant, then determine how many solution(s) it will have 12, positive= two real solutions
use quadratic formula to solve (x+6)(x-1)=-2 x=-5+/- square root 41 all over 2
a=1 b=4 c=1 use a, b, and c to find the discriminant then determine how many solution(s) it will have. x=0, zero= one real solution
2/3x^2+4/3x+1/3=0 x= -1+/- 1/2 sq root 2
Created by: lindsey94