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# Module 2 - Linear

### Module 2 - Linear Functions

Term | Definition |
---|---|

In the equation, y=3x+2, what is the slope and what is the y intercept? | The slope is 3, and the y intercept is 2. |

Given the point (7,3) and the slope being 7, give the equation in point-slope form. | Plug the points and slope into the equation: y-y1=m(x-x1) which is, y-3=7(x-7) |

Find the equation of a line passing through the given points: (-4,-3) (-6,-2) | find the slope, (rise/run) (-2-(-3))/(-6-(-4)) = -1/2 = slope. Then put the first set of coordinates into point-slope form. y-(-3)= -1/2(x-(-4)). Distribute and you get: y+3= -1/2x -4/2. Mult. both sides by 2. 2y+6=-1x-4, which = y=-1/2x-5 |

What equation form do we use to define a linear function? | Slope-intercept form. y=mx+b |

What would a graph of f(x)= 3 look like? | A horizontal line through the 3 on the y axis |

Find an equation of a line that intersects (8,-3) and parallel to 3x+4y=1 and write in standard form | Set the equation equal to y. y=-3/4x +1/4. The -3/4x will be your slope as well. Plug your points into point-slope form. y-(-3)=-3/4(x-8) and distribute and multiply both sides by 4 to get 4y+12=-3x+24. Write in standard form. 3x+4y=12 |

Find an equation of a line that intersects (3, -7) and is perpendicular to y=1/4x -2 in slope intercept form | Our slope is the negative reciprocal of 1/4x which is -4x. Then we plug the points and slope into point-slope form. y-(-7)=-4(x-3). Distribute. y+4=-4x+12. set the equation equal to y. y=-4x+5 |

Are these two lines parallel, perpendicular or neither? y=4x+23 y=4x-10 | parallel because they have the same slope |

Are these two lines parallel, perpendicular or neither? y=7x+1/2 y=-1/7x-1/2 | perpendicular because the slope is the negative reciprocal |

Created by:
samanthatrenk