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# AP Cal

integration / differentiation
∫Kf(u)du k∫f(u)du
∫[f(u)±g(u)]du u+c
∫a^u du (1/ lna) a^u +c
∫e^u du e^u +c
∫sinu du -cosu +c
∫cosu du sinu +c
∫tan u du -ln |cosu| +c
∫cotu du ln |sinu| +c
∫secu du ln |secu + tanu| +c
∫cscu du -ln |cscu + cotu| +c
∫sec^2u du tanu +c
∫csc^2u du -cotu +c
∫secutanu du secu +c
∫cscucotu du -cscu +c
∫du/√(a^2-u^2) arcsin u/a +c
∫du/ a^2 + u^2 1/a arctan u/a +c
∫du/ |u| √u^2-a^2 1/a arcsec |u|/a +c
d/dx [cu] cu^1
d/dx [u±v] u^1 ± v^1
d/dx [uv] uv^1 + vu^1
d/dx [u/v] vu^1-uv^1/ v^2
d/dx [c] 0
d/dx [u^n] nu^(n-1) u^1
d/dx [x] 1
d/dx [|u|] u/|u| (u^1) ; u≠0
d/dx [lnu] u^1/ u
d/dx [e^u] e^u u^1
d/dx [log(a)u] u^1 / (lna)u
d/dx [a^u] (lna) a^u u^1
d/dx [sinu] (cosu) u^1
d/dx [cosu] -(sinu) u^1
d/dx [tanu] (sec^2 u) u^1
d/dx [cotu] -(csc^1) u^1
d/dx [secu] (secutanu) u^1
d/dx [cscu] -(cscucotu) u^1
d/dx [arcsinu] u^1 / √(1-u^2)
d/dx [arccosu] -u^1 / √(1-u^2)
d/dx [arctanu] u^1 / 1+u^2
d/dx [arccotu] -u^1 / 1+u^2
d/dx [arcsecu] u^1 / |u|√(u^2-1)
d/dx [arccscu] -u^1 / |u|√(u^2-1)
Created by: cristinareyes95