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Chemistry D9
| Question | Answer |
|---|---|
| Polyatomic ions | Ions which are formed when a group of atoms gains or loses electrons |
| Ammonium | NH4 |
| Hydroxide | OH |
| Chlorate | ClO3 |
| Chlorite | ClO2 |
| Nitrate | NO3 |
| Nitrite | NO2 |
| acetate | C2H3O2 |
| Cyanide | CN |
| Carbonate | CO3 |
| Chromate | CrO4 |
| Dichromate | Cr2O7 |
| Molecular shape determination | Determine the Lewis structure of the molecule. |
| Molecular shape determination | If there are only two atoms in the molecule or if there are only two groups of electrons around the central atom, then the molecule must be linear and have a bond angle of 180o |
| Molecular shape determination | If there are three groups of electrons around the central atom, then the shape is trigonal with a bond angle of 120o |
| Molecular shape determination | For every non-bonding pair of electrons, you must take a “leg” of the tetrahedron away. Thus, if there are no non-bonding electrons around the central atom, the shape is tetrahedral with a bond angle of 109o |
| Molecular shape determination | If the central atom has one pair of non-bonding electrons, then you have a tetrahedron with one leg removed. This results in a pyramidal shape, with a bond angle of about 107o |
| Molecular shape determination | If two non-bonding electron pairs surround the central atom, then two legs of the tetrahedron are missing. This ends up giving the molecule a bent shape with a bond angle of approximately 105o |