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Module 25
| log(12) | 1.0792 |
| ln 16 | 2.7726 |
| log 1/100 | -2 |
| ln √e | 1/2 |
| log x=1.2 a) Type Exact Answer: b) Type 4 decimal approximation | a) 10^1.2 b) 15.8489 |
| ln x=1.3 a) Type Exact Answer: b) Type 4 decimal approximation | a) e^1.3 b) 3.6693 |
| log (3x-3) = -.07 a) Type Exact Answer: b) Type 4 decimal approximation | a) 10^-.7+3/3 b) 1.0665 |
| Suppose the $2,000 is invested at 6% interest. a) Find the amount of money in the account after 2 years if the interest is compounded annually. b) Find the amount of money in the account after 2 years if the interest is compounded continuously. | a) $22472 b) $22549.94 |
| 3^x = 6 a) Type Exact Answer: b) Type 4 decimal approximation | a) log6/log3 b) 1.6309 |
| 7^x-2 = 3 a) Type Exact Answer: b) Type 4 decimal approximation | a) 2 + log3/log7 b) 2.5646 |
| 3^8x-7 = 2 a) Type Exact Answer: b) Type 4 decimal approximation | a) 1/8(log2/log3 + 7) b) .9539 |
| e^2x = 14 a) Type Exact Answer: b) Type 4 decimal approximation | a) ln14/2 b) 1.3195 |
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