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CHEMLAB 1
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Question | Answer |
---|---|
Flame color/pH: AgNO3 | colorless/7 |
Flame color/pH: Ba(CH3COO)2 | blue green/8 |
Flame color/pH: H2SO4 | colorless/1 |
Flame color/pH: LiOH | red/13 |
Flame color/pH: MnCl2 | yellow green/7 |
Flame color:/pH K2CO3 | blue violet/13 |
Flame color/pH: Na2S | bright yellow/14 |
Flame color/pH: Cacl2 | orange red/7 |
NH4 | (-1) ammonium |
NO2 | NITRITE (-1) |
NO3 | NITRATE(-1) |
SO3 | (-2) sulfite |
SO4 | sulfate (-2) |
ClO | Hypochlorite (-1) |
ClO2 | CHLORITE (-1) |
ClO3 | Chlorate (-1) |
MnO4 | (-1) PERMANGANATE |
OH | (-1) Hydroxide |
H3O | Hydronium(-1) |
PO4 | phosphate(-3) |
CO3 | (-2) carbonate |
CN | (-1) CYANIDE |
CrO4 | (-2) CHROMATE |
Cr2O7 | (-2) dichromate |
C2H3O2 | (-1) ACETATE |
O2 | (-2) PEROXIDE |
steps to solving a net ionic equation: | 1)write balanced equation 2)rewrite full equation with separated ions. 3) remove spectator ions |
Spectator Cations (6) | Li, Na, K, Rb, Sr, Ba |
Spectator anions (6) | Cl, Br, I,NO3, CL04, SO4 |
Naming: If ion of element: | ide |
Naming:lower vs. higher O | ite, ate (hypo and per used in series of 4) ie. ClO ous,ic |
naming: prefix | 1-mono 2-di 3-tri 4-terta 5-penta 6-hexa |
oxidation number identification: | ON of element=0 ON of monoatomic ion= charge ON of 1A= +1 ON of 2A= 2 H= +1 with nonmetal H= -1 with metal O=-2 unless with peroxide (-1) F=-1 always SUM OF OXIDATION NUMBERS=CHARGE ON ION OR POLYATOMIC ION |
OXIDATION NUMBER PROCESS: | 1) elemental? 2) ionic? 3)monoatomic ion? 4)any with rules? 5) solve for those w/o rules. |
OXIDATION NUMBER:POTENTIAL | how many valence electrons is how many it can lose. only starts gaining at group 14. (for d only middle can gain e) and all group 1A metals can have -1 or +1. |
cyclohexane: | c6h12 |