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CHEMLAB 1

hell

QuestionAnswer
Flame color/pH: AgNO3 colorless/7
Flame color/pH: Ba(CH3COO)2 blue green/8
Flame color/pH: H2SO4 colorless/1
Flame color/pH: LiOH red/13
Flame color/pH: MnCl2 yellow green/7
Flame color:/pH K2CO3 blue violet/13
Flame color/pH: Na2S bright yellow/14
Flame color/pH: Cacl2 orange red/7
NH4 (-1) ammonium
NO2 NITRITE (-1)
NO3 NITRATE(-1)
SO3 (-2) sulfite
SO4 sulfate (-2)
ClO Hypochlorite (-1)
ClO2 CHLORITE (-1)
ClO3 Chlorate (-1)
MnO4 (-1) PERMANGANATE
OH (-1) Hydroxide
H3O Hydronium(-1)
PO4 phosphate(-3)
CO3 (-2) carbonate
CN (-1) CYANIDE
CrO4 (-2) CHROMATE
Cr2O7 (-2) dichromate
C2H3O2 (-1) ACETATE
O2 (-2) PEROXIDE
steps to solving a net ionic equation: 1)write balanced equation 2)rewrite full equation with separated ions. 3) remove spectator ions
Spectator Cations (6) Li, Na, K, Rb, Sr, Ba
Spectator anions (6) Cl, Br, I,NO3, CL04, SO4
Naming: If ion of element: ide
Naming:lower vs. higher O ite, ate (hypo and per used in series of 4) ie. ClO ous,ic
naming: prefix 1-mono 2-di 3-tri 4-terta 5-penta 6-hexa
oxidation number identification: ON of element=0 ON of monoatomic ion= charge ON of 1A= +1 ON of 2A= 2 H= +1 with nonmetal H= -1 with metal O=-2 unless with peroxide (-1) F=-1 always SUM OF OXIDATION NUMBERS=CHARGE ON ION OR POLYATOMIC ION
OXIDATION NUMBER PROCESS: 1) elemental? 2) ionic? 3)monoatomic ion? 4)any with rules? 5) solve for those w/o rules.
OXIDATION NUMBER:POTENTIAL how many valence electrons is how many it can lose. only starts gaining at group 14. (for d only middle can gain e) and all group 1A metals can have -1 or +1.
cyclohexane: c6h12
Created by: 1241115874