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chap 7/7

QuestionAnswer
WHY IS ENDO REACTION FASTER... COZ THE EA IN THE ENDO DIRECTION IS GREATER IN THE EXOTHERMIC REACTIONS WITH HIGH EA ARE MORE SENSITIVE TO TEMP CHANGES THAN REACTION WITH LOWER EA.
REACTIONS WITH HIGH EA ARE MORE... SENSITIVE TO TEMP CHANGES THAN REACTION WITH LOWER EA.
AFFECT OF PRESSURE ONLY APPLIES TO EQUILIBRIUM... REACTIONS IN INVOLVING GASES.
PRESSURE CAUSED BY.... BOMBARDMENT OF GAS MOLECULES ON WALLS OF CONTAINER.
A GIVEN TEMP PRESSURE DEPENDS ON ... THE NUMBER OF GAS MOLECULES IN A GIVEN VOLUME.
PRESSURE OF A EQUILIBRIUM SYSTEM CAN BE INCREASED BY.... REDUCING VOLUME, 2. ADDING MORE GAS INTO THE SAME VOLUME. MORE MOLECULES PER CM3.
THE DIRECTION OF CHANGE OF EQUILIBRIUM POS DEPENDS ON.... NO OF GAS MOLECULE (OR MOLES OF GAS) ON EACH SIDE OF EQUATION.
IF PRESSURE DECREASED LE CHATELIER’S PRINCIPLE PREDICTS ... THAT THE SYSTEM WILL REACT IN ORDER TO TRY BRING THE PRESSURE DOWN AGAIN TOWARDS THE ORIGINAL VALUE.
CAN ONLY BRING PRESSURE DOWN IF .... EQUILIBRIUM SHIFTS TO SIDE WITH FEWER GAS MOLECULES.
INCREASES IN PRESSURE (AT CONSTANT TEMP) WILL CAUSE... POSITION OF EQUILIBRIUM TO SHIFT TOWARDS SIDE OF EQUATION WITH FEWER GAS MOLECULES (FEWER MOLES OF GAS).
PREDICT OF INCREASING THE PRESSURE IN EQUATION: N2(G) + 3H2(G) REVERSE ARROWS 2NH3(G) CHANGE IN ENTHALPY -92.4KJ ... THERE ARE 4 MOLECULES ON THE LEFT SIDE OF EQUATION AND ONLY 2 ON THE RIGHT. CAUSE POSITION TO SHIFT TO SIDE WITH FEWER GAS MOLECULES. WHICH IS TO THE RIGHT.
HIGHER PRESSURES WILL INCREASE THE PROPORTION OF .... NITROGEN AND HYDROGEN THAT IS CONVERTED INTO AMMONIA.
PREDICT INCREASING THE PRESSURE IN : H2(H) +I2(G) REVERSE ARROWS 2HI(G) ENTHALPY CHANGE=+51.8KJ. .. 2 MOLES OF GAS ON EACH SIDE. INCREASE PRESSURE WILL HAVE NO EFFECT ON POSITION OF EQUILIBRIUM.
METHANE CAN BE TRAPPED IN WATER AS .... A SOLID METHANE HYDRATE (CH4(H2O)6].
REACTION BETWEEN METHANE GAS AND WATER TO FORM METHANE HYDRATE IS... EXOTHERMIC. CH4(G0 + 6H20(L) REVERES ARROW [CH4(H20)6](S)
METHANE HYDRATE FOUND AT... BOTTOM OF SEA OFF CANADIAN COAST WHERE PRESSURE HIGH.
PREDICT IF PRESSURE ON SOLID METHANE HYDRATE REDUCED TO 1ATM... SHIFT TO THE SIDE WITH MORE GAS MOLECULES. THIS MEANS METHANE HYDRATE WILL DECOMPOSE AND METHANE GAS WILL BE PRODUCED.
PREDICT WHAT WILL HAPPEN IF METHANE HYDRAE WAS HEATED... REACTION IS EXOTHERMIC. INCREASE IN TEMP WILL CAUSE EQUILIBRIUM POSITION TO SHIFT IN THE ENDOTHERMIC DIRECTION/TO THE LEFT. THUS METHANE HYDRATE WILL DECOMPOSE.
PREDICT OF METHANE HYDRATE CRYSTALS WHERE BOUGHT TO THE SURFACE OF THE SEA? ... THE SOLID METHANE HYDRATE FROM COLD OCEAN FLOOR MEANS A DECREASES IN PRESSURE AND INCREASES IN TEMPERATURE. THUS RESULTING IN METHANE HYDRATE DECOMPOSING INTO METHANE GAS AND WATER.
AFFECT ON CONC ONLY APPLIES TO SYSTEM ... WHERE THE REACTANT ARE DISSOLVED IN SOLVENT E.G. WATER
IF THE CONC SUBS IN EQUILIBRIUM REACTION INCREASED, LE CHATELIER’S PREDICTS WILL... REMOVE SOME OF THAT SUBSTANCE
TEST FOR BROMIDE AGBR(S) +2NH3(AQ) REVERES ARROWS [AG (NH3)2]+(AQ) +BR-(AQ)THE POS OF EQ.. IS NORMALLY TO THE LEFT, SO VERY LITTLE SILVER BROMIDE DISSOLVES IN DILUTE AQUEOUS AMMONIA.
HOWEVER IF CONCENTRATED AMMONIA IS ADDED .... [NH3] INCREASES. DRIVES THE POSITION OF EQ TO THE RIGHT,
CAUSING THE PRECIPITATE OF SILVER BROMIDE TO DISAPPEAR AS REACTS.
Created by: ufuoma