Pythagorean Identities

(sin^2x)+(cos^2⁡x)=1 (tan^2⁡x)+1=(sec^2⁡x) (cot^2⁡x)+1=(csc^2⁡x)

(sin2θ)=(2sinθ)(cosθ) (cos2θ)=(cos^2⁡θ)-(sin^2⁡θ) =(2cos^2⁡θ)-1 =1-(2sin^2⁡θ)

Upgrade to remove ads

Busy. Please wait.

Don't have an account? Sign up

taken

Age:

12 or younger
13 or older

Make sure to remember your password. If you forget it there is no way for StudyStack to send you a reset link. You would need to create a new account. Your email address is only used to allow you to reset your password. See our Privacy Policy and Terms of Service.

Already a StudyStack user? Log In

Reset Password

Enter the email address associated with your account, and we'll email you a link to reset your password.

Help

Options

focusNode

Didn't know it?
click below

Knew it?
click below

Don't Know

Remaining cards (0)

Know

retry

shuffle

restart

0:00

Embed Code - If you would like this activity on your web page, copy the script below and paste it into your web page.

Normal Size Small Size show me how

Precalc

Precalc terms and formulas to know

Question	Answer
Pythagorean Identities	(sin^2x)+(cos^2⁡x)=1 (tan^2⁡x)+1=(sec^2⁡x) (cot^2⁡x)+1=(csc^2⁡x)
Double Angle Formula	(sin2θ)=(2sinθ)(cosθ) (cos2θ)=(cos^2⁡θ)-(sin^2⁡θ) =(2cos^2⁡θ)-1 =1-(2sin^2⁡θ)
Factoring: a^2-b^2 Difference of Perfect Squares	a^2-b^2=(a-b)(a+b)