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Electrochemistry

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Question
Answer
oxidation   losing electrons  
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reduction   gaining electrons  
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atoms with a 0 oxidation state   atoms in their elemental form  
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atoms with a -1 oxidation state   fluorine group 17 elements (halogens)  
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atom with a +1 oxidation state   hydrogen, except when bonded to a metal: then it is -1 group 1 elements  
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atom with a -2 oxidation state   oxygen (except when it is a peroxide like H2O2) group 16 elements (oxygen family)  
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atoms with a +2 oxidation state   group 2 elements (alkaline earth metals)  
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atoms with a -3 oxidation state   group 15 elements (nitrogen family)  
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transition metal oxidation states   change according to the atoms with which they are bonded  
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reductant   reducing agent in a redox reaction, this will be oxidized  
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oxidant   oxidizing agent in a redox reaction, this will be reduced  
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electric potential, E   a potential associated with any redox reaction, can be separated into the oxidation and reduction component  
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reduction potential   electric potential describing the half reaction of a redox rxn  
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standard reduction potential   reduction potential at 25 degC - half reaction is spontaneously reduced if positive and spontaneously oxidized if negative  
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standard hydrogen electrode   2H+ + 2e' --> H2 (E = 0.00V) used to approximate electric potentials  
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strongest oxidizing agent when comparing reduction potentials   this would be the one w/ the higher (more positive) reduction potential - more spontaneously reduced  
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strongest reducing agent when comparing reduction potentials   this would be the one w/ the more negative reduction potential - more spontaneously oxidized  
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steps to balance redox rxn   1. divide rxn into half rxns 2. balance elements other than H and O 3. add H20 to 1 side until O balanced 4. add H+ to 1 side until H balanced 5. Add e- until charge balanced 6. multiply each half rxn to make e's eqal 7. add 2 half rxns and simplif  
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galvanic cell   aka voltaic cell, made of multiphase series of components w/ no component occurring in more than 1 phase but all conduct electricity but 1 is impermeable to electrons *cell potential is always positive*  
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simple galvanic cell composed of..   2 electrodes - anode and cathode  
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anode in a galvanic cell   where the oxidation half rxn takes place  
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cathode in a galvanic cell   where the reduction half rxn takes place  
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electromotive force   (emf) aka cell potential, potential difference btw the terminals when they are not connected  
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standard state cell potential   sum of the standard state potentials of the corresponding half reactions  
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salt bridge   electrolyte soln that acts as the ionic conductor that is impermeable to e's (necessary for galvanic cell) - liquid junction that minimized potential diff and allows ionic conduction btw solns w/o creating strong extra potential  
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terminal   electronic conductors (often metal wires), symbolized as T  
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galvanic cell symbolized -   T-E-I-E'-T' where T are the terminals, E are the electrodes, and I is the ionic conductor (often salt bridge)  
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what would happen if a galvanic cell didn't have a salt bridge   the solns of the galvanic cell would mix providing a low resistance path for e's to move from the anode to the cathode effectively short circuiting the cell and leaving it with a potential of zero  
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free energy and cell potential eqn   delta(G) = -n*F*Emax n is the moles of e' transferred, F is Faraday's constant, E is the cell potential  
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positive cell potential indicates ___ free energy   negative meaning rxn is spontaneous  
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free energy relating to reaction quotient eqn   delta(G) = delta(Go) + RTln(Q) where Q = Products/Reactants  
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standard free energy eqn (relating to equilibrium constant)   delta(Go) = -RTln(K)  
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what are the qualitative relationships btw K and standard free energy   if K = 1, then delta(Go) = 0 if K > 1, then delta(Go) < 0 if K < 1, then delta(Go) > 0 **remember this is standard state  
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Nernst eqn   E = Eo - (RT/nF)ln(Q) expresses the relationship btw chemical concentrations and potential difference  
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concentration cell   limited form of galvanic cell with reduction half rxn taking place in 1 half cell and the EXACT reverse of that half rxn taking place in the other half cell, NEVER at standard conditions, requires use of Nernst eqn to solve - tend to have small potentials  
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in what direction will current flow in the concentration cell?   think about which will create the greatest entropy - the more concentrated side will try to become less concentrated and the e's will flow accordingly  
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electrolytic cell   has NEGATIVE emf, rxns are forced by outside power source where cathode is negative and anode is positive but reduction still takes place at cathode and oxidation at anode  
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