Bag o' Tricks Word Scramble
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Question | Answer |
__+__=__ | segment addition postulate/angle addition postulate |
angle is congruent to angle | vertical angles are congruent |
midpoint <-> =/congruent | definition of midpoint |
bisector of angle <-> =/congruent | definiton of angle bisector |
midpoint <-> 1/2 | midpoint theorem |
bisector of angle <-> 1/2 | angle bisector theorem |
midpoint <-> bisects | definiton of segment bisector |
90 <-> right | definition of segment bisector |
complimentary <-> =90 | definition of complimentary angles |
supplementary <-> =180 | definition of supplementary angles |
perpendicular lines -> right right -> perpendicular lines perpendicular lines -> 90 90 -> perpendicular lines | definition of perpendicular lines |
perpendicular lines -> congruent | if perpendicular lines, then congruent adjacent angles |
congruent -> perpendicular | if congruent adjacent angles, then perpendicular lines |
perpendicular lines -> complimentary | if exterior sides of two acute adjacent angles are perpendicular lines, then the angles are complimentary |
complimentary, complimentary, congruent -> congruent | compliments of congruent angles are congruent |
complimenary, complimentary -> congruent | compliments of the same angle are congruent |
supplementary, supplementary, congruent -> congruent | supplements of congruent angles are congruent |
supplementary, supplementary -> congruent | supplements of the same angle are congruent |
addition property | if a=b and c=d, then a+c=b+d |
subtraction property | if a=b and c=d, then a-c=b-d |
multiplication property | if a=b, then ca=cb |
division property | if a=b and c is not equal to 0, then a/c=b/c |
substitution property | if a=b, then either a or b may be substituted for the other in any equation (or inequality) |
reflexive property | a=a |
symmetric property | if a=b and b=c, then a=c |
transitive property | if a=b and b=c, then a=c |
distributive property | if a(b+c), then ab+ac |
reflexive property (congruence) | line segment DE is congruent to line segment DE angle D is congruent to angle D |
symmetric property (congruence) | if line segment DE is congruent to lene segment FG, then line semgent FG is congruent to line segment DE if angle D is congruent to angle E, then angle E is congruent to angle D |
transitive property (congruence) | if line seg. DE is congruent to line seg. FG and line seg. FG is congruent to line seg. JK, then line seg. DE is congruent to line seg. JK if angle D is congruent to angle E and angle E is congruent to angle F, then angle D is congruent to angle F |
Created by:
Monkeyboy1518
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