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Real Analysis UHH

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Question
Answer
A number set is compact iff   it is closed and bounded.  
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[0,1] is   compact  
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C[0,1] is   compact and complete  
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Uniform continuity is   compact  
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Reals are   complete  
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Rationals are not   compact and complete  
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Iff f is continuous   then if p is in D and c>0 then there is a d>0 such that if x is in D and |x-p|  
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Iff f is continuous   then if U is an open set, then f-1(U) is open relative to D.  
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Iff f is continuous   then if p is in D and S is a sequence in D with limit p, then the sequence T defined by T(n)=f(S(n)) has limit f(p).  
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Iff U is a closed set in f(D)   then f-1(U) is closed relative to D.  
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If f is continuous over the compact set A and c > 0   then there is a d > 0 such that if each of x and y is in A and |x - y| < d, then |f(x) - f(y)| < c.  
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Let D be a subset of the reals and for each positive integer i, let fi:D  R. The statement that this sequence of functions converges pointwise means that   for each p in D the number sequence Sp defined by Sp(n) = fn(p) has limit.  
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The statement that the function f:[a,b]-->R is of bounded variation (denoted by B.V.) means   there is a number M > 0 such that if x1, x2,...,xn is a subdivision of [a,b] then Integral < M.  
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If sequences are complete   then converge  
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If sequence is Cauchy   then it has no holes  
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The statement that the sequence of functions f=f1,f2,.... converges uniformly to f:[a,b]-->R means   if c>0, there exists a N∈Z+ s.t. if i>N and x∈[a,b], then [fi(x)-f(x)]  
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Diatic Rationals (1/2^n)   are dense  
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The statement that a set is dense means   every point in the set is a limit point  
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The statement that a set is dense means   its closure is the whole set  
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Rationals are   dense on the reals  
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Hypothesis for Intermediate Value Theorem   Horizontal line test  
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