Busy. Please wait.
Log in with Clever
or

show password
Forgot Password?

Don't have an account?  Sign up 
Sign up using Clever
or

Username is available taken
show password


Make sure to remember your password. If you forget it there is no way for StudyStack to send you a reset link. You would need to create a new account.
Your email address is only used to allow you to reset your password. See our Privacy Policy and Terms of Service.


Already a StudyStack user? Log In

Reset Password
Enter the associated with your account, and we'll email you a link to reset your password.

Probabilities, combinitorics, permutations

Quiz yourself by thinking what should be in each of the black spaces below before clicking on it to display the answer.
        Help!  

Question
Answer
P(E)   # of ways E can occur ______________________ total possible outcomes  
🗑
Sample Space   collection of all possible outcomes  
🗑
Event   a collection of outcomes  
🗑
outcome   any ONE thing that can happen  
🗑
in a regular 52 card deck what is the probability of getting an ace?   4 ___ 52  
🗑
Empirical Probability   Counting observation, changes by observation # of times E occurred/ total # of observations  
🗑
Contingency table   make a grid to figure out the probabilities  
🗑
The Law of Large Numbers (difference gets smaller w/ more observations)   as you increase the number of observations the probability increases. P(|Pemp(E)-Pcl(E)|>S) -> 0  
🗑
Make a list   STAT ENTER  
🗑
_ X   Sample Mean  
🗑
SX   sample standard deviation  
🗑
OX   Population Standard Deviation  
🗑
n   Sample Size  
🗑
Med   Median (50% mark)  
🗑
To compute 2 lists of descriptive stats   STAT > ENTER enter data in list > STAT > CALC > > ENTER > 2ND > 1,2 (etc - use comma)  
🗑
Permutation = NPR   the number of ways to arrange r objects from a larger set of n objects. (one at a time) in a 52 card deck, how many ways to arrange?  
🗑
Combination = NCR   What is the probability of getting X from A any order?  
🗑
Combination - What is the probability of getting a 5 card hand, all spades.   13 spades 13 c 5 cards ____________ 52 c 5 cards = 4.95 x 10-4  
🗑
Permutation - In a 52 card deck how many 5 card hands are there?   52 c 5 = (math PRB NCR enter 5 enter)  
🗑
n factorial   The number of way to arrange n objects n MATH PRB ! ENTER ENTER  
🗑
52 card deck arrange 7 cards on table, how many ways   52 P 7 = 52 MATH PRB NPR ENTER (52 npr) 7 ENTER  
🗑
How many ways can you choose 5 people from a class of 50?   50 p 5 50 MATH PRB NPR ENTER (50 NPR) 5 ENTER  
🗑
Complimentary Probability   Given E, its opposite E is its compliment P(E) + P(E!)=1 so, P(E) = 1-P(E!)  
🗑
Complimentary Prob - in a 52 card deck what is probability of getting one ace in 5 card hand?   opposite of getting one ace is no ace = 1 - 48 C 5 / 52 C 5 (48 cards = 52 - aces - 1 ace in your hand)  
🗑
Conditional probability   Given 2 events (E given F) "Given a 52 card deck, what is the probability getting 5 spades, given all cards are black."  
🗑
Given a 52 card deck, what is the probability getting 5 spades, given all cards are black   P (5 spades/ black) #ways to get 5 spades # ways black 5 card hands spades 13 C 5 / 26 (black cards) C 5 = .0195  
🗑
Independence (2 events)   P(E given F) = P(E) Independent if proportion are the same dependent of proportions are not the same.  
🗑
Are aces independent of hearts?   P (ace/hearts) vs P(aces/cards) ace in hearts/# hearts = # aces /total # cards 1/13 = 4/52 (1/13) independent  
🗑
Binomial Distribution (Bernouli) Roulette = Bernouli Poker blackjack = not bernouli   Finite trials, 2 events (success vs fail), P(success) same from trial to trial, trials are independent  
🗑
The probability of getting the flu is 18% Out of 10 friends, what is the probability of: between 2 and 4 get the flu   P(X<n)=binom cdf (n [# of trials], p [probability of success],n [number of success])  
🗑
What is the probability of sick at c- restaurant is 15%, out of 5 visits that you'll get sick twice?   Note exact # (Binom pdf) 2nd VERS BINOMPDF (5,.15, 2) visits possible, %, sick actual  
🗑
What is the probability of sick at c- restaurant is 15%, out of 5 visits that you'll get sick AT LEAST twice?   Note range (Binom cdf) 1 - BINOMCDF (5, .15, 2) opposite of 2 or more - visits poss, %, top range - 1  
🗑
Geometric Distribution: Basketball player has 54% free throw average. What is the probability he misses 4 and makes the 5th   Note: Probability of 1st success on nth try 2nd VARS GEOMETCDF (.54, 5) (never pdf) probability, tries  
🗑
If the probabilty of getting a role in a movie is 2.1%, what is the probability of getting it for the first time on the 1th try?   2nd VARS GEOMETPDF (.021, 10) = .0173  
🗑
What is the probability of winning the lottery in your working lifetime: play once a week for 30 years   52 x 30 = 1560 times (3 steps incl. prob) 1/50 nCr 5 X 45 nCr 1 1 #/50 pos #s nCr 5# X 45 remaining # nCr 1 last # = 1.048 X 10-8 FINAL STEP: 1 - binompdf (1560, 1.05x10-8)  
🗑
Given that the probability of being accepted by an ivy league school is 4.2%, what is the probability of: Getting in after 3 rejections?   Specific # but no order GeometPDF (.042, 4) [after 3 means 4] .00369  
🗑
Given that the probability of being accepted by an ivy league school is 4.2%, what is the probability of: getting in if you apply 4 times   Exact # BinomPDF (4, .042, 1) = .1477 tries, %, success  
🗑
The Poisson Distribution computing averages given data over time   is used when: potentially infinite # of trials Trials are independent you have an average # of success per trial 4 errors/sec 5 strokes/ hole  
🗑
Max safety level for ameb dysentary is 6 live org per liter. what is probability you get 7 live org?   P(X) = Poisson PFD Exact P(<X) = Poisson CDF Range (7-1 = 6) 1 - PoissonCDF (6,6) = .3937 average,(7-1=6)  
🗑
An internet service provider can handle up to 32 customers/sec what is the probability that any 5 sec intreval has at least 145 customers/ sec?   Average # success - Poisson dist. 32 cust/sec x 5 sec = 160 AVERAGE MAX 1 - POISSONCDF (160, 144) = .8911 average, X (145 - 1 + 144)  
🗑
Fatal auto accident rate in a suburb is 1/4500/year If the suburb has a population of 180,000 what is the probability of no more than 2 fatal accidents in a given year?   1/45,000 into 180,000 = 4 POISSONCDF (4,2) = .23810 average,X  
🗑
Is the range open ended? (either end) Asking for probability? Draw out Graph, Mean is the center point   NormalCDF continuous-U or L parameter is missing (10 99,L,M,O) (U,10 99,M,O) NORMALCDF (U, L, M, O)requires upper & lower Upper, Lower, Mean, Standard Deviation  
🗑
Empirical Rule: Standard Normal Distribution    
🗑


   

Review the information in the table. When you are ready to quiz yourself you can hide individual columns or the entire table. Then you can click on the empty cells to reveal the answer. Try to recall what will be displayed before clicking the empty cell.
 
To hide a column, click on the column name.
 
To hide the entire table, click on the "Hide All" button.
 
You may also shuffle the rows of the table by clicking on the "Shuffle" button.
 
Or sort by any of the columns using the down arrow next to any column heading.
If you know all the data on any row, you can temporarily remove it by tapping the trash can to the right of the row.

 
Embed Code - If you would like this activity on your web page, copy the script below and paste it into your web page.

  Normal Size     Small Size show me how
Created by: onesmartgirl
Popular Math sets