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Quadratic Functions and their Graphs

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Question
Answer
If a>0, the graph of the quadratic function opens which way?   Upward  
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If a<0, the graph of the quadratic function opens which way?   Downward  
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The vertex of a parabola defined by f(x)=a(x-h)^2+k has a vertex defined by the values of which variables?   (h,k)  
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What is the vertex of the quadratic function g(x)= (x-4)^2-2?   (4,2)  
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What is the vertex of the quadratic function f(x)= 3(x-8)+6?   (8,6)  
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In the equation f(x)=(x-2)+6, is h positive or negative?   Positive  
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In the equation f(x)=(x+9)+3, is h positive or negative?   Negative  
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In graphs with the equation f(x)=x^2+k, what happens to the graph when k is negative?   The graph will shift |k| downward from y=x^2  
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In graphs with the equation f(x)=x^2+k, what happens to the graph when k is positive?   The graph will shift |k| upward from y=x^2  
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In graphs with the equation f(x)=(x-h)^2, what happens to the graph when h is positive?   The graph will shift h units to the right from y=x^2  
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In graphs with the equation f(x)=(x-h)^2, what happens to the graph when h is negative?   The graph will shift h units to the left from y=x^2  
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What is another name for the vertex (h,0)?   The x-intercept  
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What is another name for the vertex (0,k)?   The y-intercept  
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In a parabola defined by f(x)=a(x-h)^2+k, when the absolute value of a is greater than 1, how does the graph compare to the graph of y=x^2?   The graph is narrower than y=x^2  
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In a parabola defined by f(x)=a(x-h)^2+k, when the absolute value of a is less than 1, how does the graph compare to the graph of y=x^2?   The graph is wider than y=x^2  
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How do you determine a parabola's axis of symmetry?   The axis of symmetry is the same as the value of h; if h=4, then the axis of symmetry is x=4  
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For f(x)=x^2+2, state the vertex, axis of symmetry, and whether the parabola opens upward or downward.   (0,2), x=0, downward  
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The graph of f(x)=ax^2+bx+c when a is not 0 is a parabola with a vertex of what?   (-b/2a, f(-b/2a))  
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How do you solve an equation by completing the square?   Add the square of half the coefficient of x, and then use the square root property to get two solutions.  
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Make a perfect square trinomial from x^2+12x   x^2+12x+36  
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