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Exponential Function
module 23
| Question | Answer |
|---|---|
| 5^x=125 | Rewrite equation so 125 is expressed as a power of 5. 5^x=5^3. Therefore x=3 |
| 81^x-1=9^3x | Write 81 & 9 as powers of 3. (3^4)^x-1=(3^2)^3x. simplify 3^2x-2=3^9x. Put the exponents to equal 2x-2=9x and then solve for x. |
| y=240(2x7) | Plug in the numbers you know. 30=t. Multiply 0.015 and 30 which equals 0x45. Then take 2.7 ^0.45 power 1.56. the answer comes to 375. |
| 16^x=32 | x=5/4 |
| Find the amount Tom owes at the end of 4 years if $5200 is loaned to her at a rate of 5% compounded monthly. | $6348.66 use A=P(1+r/n)^nt P=$5200 r=5%=0.05 t=4 |
| Graph y=7^x | Get ordered pairs by making a x,y chart. Using 0, -1, 1. you get (0,1)(-1,1/7)(1,7). Then graph the points and draw a line through them. |
| 625^x=3125 | x=5/4 |
| 27^x-1=81^3x | x=-1/3 |
| 3^x=81 | x=4 |
| 125^x=625 | x=4/3 |
Created by:
samanthazerilli
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