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Ch.6 Conjectures

Conjecture NameWhat it states
Intersecing Secants Conjecture angle formed by secants that intersect out of circle= 1/2difference of arcs
Intersecting Chords Conjecture angle formed by 2 intersecting chords is 1/2sum
Tangent-Secant Conjecture angle formed by intersecting tangent and secant is 1/2difference
Intersecting Tangents Conjecture angle formed by 2 intersecting tangents to a circle=1/2difference
Tangent Chord Conjecture angle formed by intersecting tangent and chord at pt. of tangency=1/2arc
Circumference Conjecture C=d*pie
Arc Length Conjecture arc length=arc measure/360 * circumference
Inscribed Angle Conjecture msr of inscribed angle is 1/2 arc
Inscribed Angle Intercepting Arcs Conjecture inscribed angles that intercept the same arc/or congruent arcs, are congruent
Angles Inscribed in a Semicircle Conjecture angles inscribed in a semicircle are right angles
Cyclic Quadrilateral Conjecture opp. angles of a cyclic quad. are supplementary
Parallel Lines Intercepted Arcs Conjecture parallel lines intercept congruent arcs on circle
Chord Central Angles Conjecture congruent chords->congruent angles
Chord Arcs Conjecture congruent chords->congruent arcs
Perpendicular to a Chord Conjecture perpendicular from center of circle to a chord is its bisector
Chord Distance to Center Conjecture 2 congruent chords in a circle are equidistant from center of circle
Perpendicular Bisector of a Chord Conjecture perpendicular bisector of a chord passes thru the center
Tangent Conjecture a tangent to a circle is perpendicular to the radius at pt of tangency
Tangent Segments Conjecture tangent segments to a circle from a pt. outside the circle are congruent
Created by: VaLeRiA!