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Jordan Math
Integrals and Derivative formula's
Question | Answer |
---|---|
Derivative of Sinx | Cosx |
Derivative of Tanx | (secx)^2 |
Derivative of Secx | SecxTanx |
Derivative of Cosx | -Sinx |
Derivative of Cotx | -(Cscx)^2 |
Derivative of Cscx | -(CscxCotx) |
Integral of A^u | (1/ln(A))A^u |
Integral of Tanu | -ln|cosu| |
Integral of Cotu | ln|sinu| |
Integral of Secu | ln|Secu+Tanu| |
Integral of Cscu | -ln|Cscu+Cotu| |
Integral of (1/sqr[A^2-u^2]) | Arcsin (u/a) |
Integral of (1/[A^2+u^2]) | (1/A)Arctan(u/A) |
Integral of (1/[u*sqr[u^2-A^2]]) | (1/A)Arcsec(|u|/A) |
When doing the integral X^(n)e^(ax) what should your dv and u be? | u=X^(n) dv=e^(ax) |
When doing the integral X^(n)Sin(ax) what should your dv and u be? | u=X^(n) dv=Sin(ax) |
When doing the integral X^(n)Cos(ax) what should your dv and u be? | u=X^(n) dv=Cos(ax) |
When doing the integral X^(n)ln(x) what should your dv and u be? | dv=X^(n) u=ln(x) |
When doing the integral X^(n)arcsin(ax) what should your dv and u be? | dv=X^(n) u=arcsin(ax) |
When doing the integral X^(n)arctan(ax) what should your dv and u be? | dv=X^(n) u=arctan(ax) |
When doing the integral e^(ax)Sin(bx) what should your dv and u be? | u=Sin(bx) dv=e^(ax) |
Derivative of Arcsin(u) | (u'/sqr[1-u^2]) |
Derivative of Arccos(u) | (-u'/sqr[1-u^2]) |
Derivative of Arctan(u) | (u'/1+u^2) |
Derivative of Arcsec(u) | (u'/|u|sqr[u^2-1]) |