Busy. Please wait.

Forgot Password?

Don't have an account?  Sign up 

show password


Make sure to remember your password. If you forget it there is no way for StudyStack to send you a reset link. You would need to create a new account.

By signing up, I agree to StudyStack's Terms of Service and Privacy Policy.

Already a StudyStack user? Log In

Reset Password
Enter the email address associated with your account, and we'll email you a link to reset your password.

Remove ads
Don't know (0)
Know (0)
remaining cards (0)
To flip the current card, click it or press the Spacebar key.  To move the current card to one of the three colored boxes, click on the box.  You may also press the UP ARROW key to move the card to the "Know" box, the DOWN ARROW key to move the card to the "Don't know" box, or the RIGHT ARROW key to move the card to the Remaining box.  You may also click on the card displayed in any of the three boxes to bring that card back to the center.

Pass complete!

"Know" box contains:
Time elapsed:
restart all cards

Embed Code - If you would like this activity on your web page, copy the script below and paste it into your web page.

  Normal Size     Small Size show me how

Absolute Value

Absolute Value Equations and Inequalities

|x| = 21 Recall that if |x| = a and a is positive, then x = a or x= -a. so |x| = 21 is equal to x = 21 or x = -21. Solution set is {21,-21}.
|2x-9| = 13 Since 13 is positive |2x-9| = 13, is equal to 2x-9 = 13 or 2x-9 = -13 2x = 22 or 2x = -4 x = 11 or x = -2 Solution set is {-2,11}
|5x| = 0 if a is 0 then x is 0. meaning |5x| = 0, is equal to 5x = 0. So 5x = 0 divide both sides by 5 x = 0 solution set is {0}
write an absolute value equation representing all numbers x whose distance from 0 is 15 units. The absolute value of a number x is equal to 15. solution is |x| = 15
solve |x+12| = |x-5| x+12 = x-5 12 = 5 no solution or x+12 = -(x-5) x+12 = -x+5 2x+12 = 5 2x = -7 x = -7/2 Solution set is {-7/2}
|7x+7|>0 The solution is all real numbers except the numbers that make x+7 equal to 0. First find the number that would make it 0. 7x+7 = 0 x = -1 So the solution is all real numbers except -1. solution set is (-∞, -1)U(-1,∞)
|x+5| = -30 The absolute value expression is set to equal a negative number, so the solution is: NO solution.
|2x+5|+6<25 First isolate the absolute value. subtract 6 from both sides. 2x+5<19, since 19 is positive set up as -a<x<a. -19<2x+5<19,now solve -24<2x<14 -12<x<7 solution is (-12,7)
Created by: s0498920