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# 22- Inverse Function

Question | Answer |
---|---|

Determine one-to-one function. Write inverse function. f = {(-1,-1), (1,1), (0,2), (2,0)} | one-to-one function; f^-1 = {(-1,-1), (1,1), (2,0), (0,2)} |

Given: f(x) = x^3 + 2 Find: f(1) and f^-1(3) | f(1) = 1^3 + 2 f(1) = 1 + 2 f(1) = 3 f^-1(3) = 1 |

Determine one-to-one function. Write inverse function. f = {(10,10)} | one-to-one function; f^-1 = {(10,10)} |

Given: f(x) = x^3 + 2 Find: f(-1) and f^-1(1) | f(-1) = -1^3 + 2 f(-1) = -1 + 2 f(-1) = 1 f^-1(1) = -1 |

Determine one-to-one function. Write inverse function. f = {(0,3), (3,7), (6,7), (-2,-2)} | NO SOLUTION! The y-values of the coordinates (3,7) and (6,7) are both 7. |

Write the inverse of... f(x) = x + 4 | f^-1(x) = x + 4 S1.) y = x + 4 S2.) x = y + 4 S3.) x - 4 = y S4.) f^-1(x) = x - 4 |

Write the inverse of... f(x) = 2x - 3 | f^-1(x) = 2x - 3 S1.) y = 2x -3 S2.) x = 2y -3 S3.) x + 3 = 2y...x+3/2 = y S4.) f^-1(x) = x+3/2 |

One-to-one function? State (input): CA, IL, MI, WI, FL Votes (output): 77, 65, 48, 59, 39 | yes; no state or votes is listed more than once. |

Write the inverse function of... f(x) = 5x + 2 | f^-1(x) = 5x + 2 S1.) y = 5x + 2 S2.) x = 5y + 2 S3.) x - 2 = 5y... y = x-2/5 S4.) f^-1(x) = x-2/5 |

Write the inverse function of... f(x) = 1/3x - 1 | f^-1(x) = 1/3x - 1 S1.) y = 1/3x - 1 S2.) x = 1/3y -1 3(x+1 = 1/3y) y = 3x + 3 S4.) f^-1(x) = 3x + 3 |

Created by:
danap