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Complex numbers
Question | Answer |
---|---|
Write with i notation. √-49? | √-49 = √-1 * √49 =7i |
Multiply √-49 * √-1 | 7i(i)=7i^2=7(-1)=-7 |
Add the complex numbers. (2+4i)+(-3+2i) | (2-3)+(4+2)i=-1+6i |
subtract the complex numbers. 7i-(1-i) | 7i-1+1=-1+(7+1)i=-1+8i |
Multiply the complex numbers. Write in the form a+bi. | 2i(3-i)=2i*3-2i*i=6i-2i^2=6i-2(-1)=6i+2=2+6i |
Divide, write in the form a+bi.4+i/1-i | (4+i)(1+i)/(1+i)(1+i)= 4+4i+i-1/1+1=3/2+5/2i |
Find the power of i. i^20 | (i^4)^5=1^5=1 |