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Химия ЕГЭ 2023 ОВР

1-16

QuestionAnswer
KMn+7O4 (кислая среда) Н+ KMn+7O4 + Na2S+4O3 + H2SO4 = Mn+2 + H2O (обесцвечивание) = K2SO4 + Mn+2SO4 + Na2S+6O4 + H2O
KMn+7O4 (нейтральная среда) Н2O KMn+7O4 + Na2S+4O3 + H2O = Mn+4O2 + KOH (бурый) = KOH + Mn+4O2 + Na2S+6O4
KMn+7O4 (щелочная среда) KOН KMn+7O4 + Na2S+4O3 + KOH = K2Mn+6O4 + H2O (зеленый) = K2Mn+6O4 + Na2S+6O4 + H2O
MnO2 + KCl + H2SO4 = = MnSO4 + K2SO4 + Cl2 + 2H2O
K2MnO4 + HCl(конц.) = = KCl + MnCl2 + Cl2 + H2O
K2MnO4 + H2O = = MnO2 + KMnO4 + KOH
K2MnO4 + Cl2 = = KCl + KMnO4
K2Cr2+6O7 (кислая среда) (оранжевый) Н+ K2Cr2O7 + Na2SO3 + H2SO4 = Cr+3 + H2O = K2SO4 + Cr2(SO4)3 + Na2SO4 + H2O (зеленый)
K2Cr+6O4 (нейтральная среда) (желтый) Н2O K2Cr2O7 + Na2SO3 + H2O = Cr+3(OH)3 + KOH (серо-зеленый) = KOH + Cr(OH)3 + Na2SO4
K2Cr+6O4 (нейтральная среда) (желтый) KOН K2CrO4 + Na2S + H2O = Cr+3(OH)3 + H2O (серо-зеленый) = KOH + Cr(OH)3 + S + NaOH
H2SO4(конц.) + Сu = = СuSO4 + SO2 + H2O
H2SO4(конц.) + С = = CO2 + SO2 + H2O
H2SO4(конц.) + H2S = = S + SO2 + H2O
H2SO4(конц.,кип.) + H2S = = SO2 + H2O
H2SO4(конц.) + Mg = = MgSO4 + H2S + H2O
H2SO4(конц.) + KI = = K2SO4 + H2S + I2 + H2O
H2S+6O4(конц.) - слабый восстановитель ( S, P, C, средне- и малоактивные металлы: Fe, Cu, Ag ... сложные вещества: H2S, ... ) S+4O2 + H2O
H2S+6O4(конц.) - сильный восстановитель (активные металлы: Li - Zn ... некоторые сложные вещества: HI, KI, ... ) H2S-2, S + H2O
Created by: Kasatka3456
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