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Test 2 & 3

Math for Teachers I

QuestionAnswer
1-1 correspondence a pairing of the elements of A with the elements of B so that each element of A corresponds to exactly one element of B, and vice versa.
set A collection of objects
elements or members the objects of the set
Mayan 360s 20s 1-19
babylonian 3600 60 under 60
I 1
V 5
X 10
L 50
C 100
D 500
M 1,000
If a number is deficient, it is prime. FALSE 4 IS DEFICIENT AND NOT PRIME.
If a number is prime, it is deficient. True
If 4|n and 6|n, then 24|n. FALSE 4|12 AND 6|12 BUT 24 DOESN’T DIVIDE 12.
If 5|n and 3|n, then 15|n TRUE
If a|n, then there is a number b such that a times b = n TRUE
1,260 has exactly 6 factors. FALSE 48 FACTORS
If n is divisible by 24 it is also divisible by 4 and 6. TRUE
561 is a prime number. FALSE 3|561
One is a prime number FALSE ONE HAS NOT PROPER FACTORS.
All prime numbers are odd FALSE TWO IS PRIME AN EVEN.
If 12|n, then 3|n TRUE
To decide if 36 divides a number, you can try 4 and 9. If 4 and 9 divide the number, then 36 divides the number True
If n is divisible by 4 and 6 it is also divisible by 24 FALSE: 4|12 AND 6|12 BUT 24 DOESN’T DIVIDE 12.
32|4 FALSE THERE DOES NOT EXIST A WHOLE NUMBER B SUCH THAT 34 • B = 4.
Every prime number greater than 2 is one more than an odd number FALSE EVEN
To determine if a number is divisible by 11, add its digits. If 11|sum, 11|number. FALSE, CIRCLE EVERY OTHER DIGIT. ADD THE CIRCLED DIGITS. ADD THE OTHER DIGITS. FIND THE DIFFERENCE OF THESE TWO SUMS. IF 11|THIS DIFFERENCE, 11|THE NUMBER.
GCF (a,b) + LCM (a,b) = a• b. FALSE, GCF (a,b) • LCM (a,b) = a• b
Consider 12, 447, 2d2. What digit should "d" be for this number to be divisible by 18. List all possible answers. 5
2. Consider 14, d27, 120. What digit should "d" be for this number to be divisible by 20. List all possible answers Any digit or 0,1,2,3,4,5,6,7,8,9
3. Consider 31, 106, 23d. What digit should "d" be for this number to be divisible by 12. List all possible answers. 2
4. Consider 12, 447, 2d2. What digit should "d" be for this number to be divisible by 24. List all possible answers. Since d must be 3 or 7 to pass the 8 rule, and neither of these will result in a sum of digits that is divisible by 3, the answer is: NO POSSIBLE DIGIT.
Show that you know the process for determining if 214,516,318,199 is divisible by 11. Sum of circled digits = 2 + 4 + 1 + 3 + 8 + 9 = 27 Sum of other digits = 1 + 5 + 6 + 1 + 1 + 9 = 23 27 – 23 = 4 Since 11 does not divide 4 it does not divide the given number.
Created by: 732970859
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