click below
click below
Normal Size Small Size show me how
phyx eqns mechanics
Question | Answer |
---|---|
Kinematic for final velocity | vf = at + vi |
Kinematic for final velocity squared | vf ^ 2 = vi ^2 + 2ax |
Kinematic for displacement | x= vi t + 1/2 at^2 |
Displacement with constant acceleration | Δx = ½ (vf + vi) Δt |
Newton's Law of Gravity | F= (G m1 m2)/ r^2 |
Coulomb's Law | F = (k q1 q2)/ r^2 |
Apparent Weight | F = mg +ma |
Static Friction | F= us FN |
Kinetic Friction | F = uk FN |
velocity in rotational motion | v = 2πr / t |
Centripetal Acceleration | ac= v^2/r |
Centripetal Force | Fc= mv^2/ r or Fc = mac |
Work | W = Fx |
Kinetic Energy | KE = 1/2 mv^2 |
Gravitational Potential Energy | PE= mgh |
Elastic Potential Energy | PEe= 1/2 kx^2 |
Impulse | I = Ft |
Momentum | p = mv |
Position of the Center of Mass | x = m1x1 + m2x2 / (m1 + m2) |
Velocity of the Center of Mass | v = m1v1 + m2v2 / (m1 + m2) |
Position of the Center of Gravity | x = W1x1 + W2x2 / (W1 + W2) |
Torque | T= F l |
Angular Momentum | L = I w |
Moment of Inertia | I = mr^2 |
Angular velocity | w = θ /t ( in radians θ = l/r ) l= arc length |
Rotational Kinetic Energy | KEr = 1/2 I w^2 or 1/2 mr^2 w^2 |
Angular Acceleration | α = w/ t |
Hooke's Law | F= -kx |
Rotational Velocity | w = 2πf |
Period of a Pendulum | T = 2π √ (L/g) |
Period of a Spring | T = 2π √ (m/k) |
Power (two) | P = W/t or P = Fv |
Period | T = 2π / w |
Maximum velocity of a of a rotating object | v = Aw or use KE at equilibrium |