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chem exam 4
chem 102
Question | Answer |
---|---|
Alkanes | CnH2n+2 Only single bonds saturated hydrocarbons anes |
meth | 1 carbon |
eth | 2 carbon |
prop | 3 carbon |
but | 4 c's |
pent | 5 c's |
hex | 6 c's |
hept | 7 c's |
oct | 8 c's |
complete structual formulas | shows connectivity of every atom |
condensed structual formulas | shows c's and the # of h's it is attached to |
structual isomers | same formula different structures |
NH2 | AMINO |
NO2 | NITRO |
F | FLUORO |
CH=CH2 | VINYL |
Cl | CLORO |
OH | HYDROXY |
Br | BROMO |
I | IODO |
naming alkanes | 1. find longest carbon chain 2. use appropriate root based on # of c's in longest chain 3. ane prefix 4. name branches 5. organize branch names abc method 6. use carbon numbers to designnate location of branches |
alkane combustion | something + O2= CO2+ H2O balance equation |
alkane halogenation | replace 1 or more h atoms with halogens remove one H and one halogen to create "HCl" remaining halogen combines w/ organic compound use di,tri, or tetra to designate #of halogens |
alkenees | contain at least one C=C CnH2 n= # of n's / 2 enes # carbon chain from end closest to = bond designate double bond location with number |
geometric isomers | cis and trans put cis/trans before last part of name |
alkene hydrogenation | = breaks and replaced with H's -degraded to alkane |
alkene halogenation | = breaks and replaced with Halogen =chloro, flouro, bromo attached to last part of name w/ location ex: 2-chloropropane |
Alkynes | at least one carbon triple bond CnH2n-2 |
alkyne combustion | something + O2= CO2+ H2O balance equation |
alkyne decomposition | split CH E CH= 2C +H2 |
alkyne hydrogenation | E breaks and replaced with H's -degraded to alkene |
alkyne halogenation | E breaks and replaced with Halogen =chloro, flouro, bromo attached to last part of name w/ location ex: 2-chloropropene moles indicate removal of bond amount |
aromatics | contain at least on benzene |
naming aromatics | - if one sub, put sub name followed by benzene -if more than one of same sub, use numbering system (lowest number possible) use omp (1,2/1,3/1,4) (ortho,meta, para - if different subs , go by lowest number then abc method |
polycyclic aromatics | more than 1 benzene fused together |
naphtalene | 2 benzenes |
anthracene | 3 benzenes |
aromatic hydrogenation | - only posible at high temps, and pressure - add Hs |
aromatic substitution | remove a H from a benzene corner and replace with one of the ions leaving ex: bromobenzene +HBr |
aromatic alkyl substitution | done with catalyst like CH3CH2Cl -remove a H from a benzene corner and replace with one of the alkyl groups - combine removed H with catalyst to create "HCl" |
phenyl | Benzene as a sub |