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Module 11
Radicals and Radical Functions
Question | Answer | reason |
---|---|---|
3√8 index of 3 square root of 8 | 2 | 2*2*2=8 |
√47 square root of 47 use approximate | 6.856 | 6.856 * 6.856=approximate 47 |
3√-1/8 index of 3 square root of fraction -1/8 | -1/2 | -1/2 * -1/2 * -1/2 = -1/8 |
√(-2)² square root of -2 to the 2nd power | Ι2Ι | absolute value 2 square root of 4 is 2 |
√(x-4)² square root of (x-4) to second power | Ιx-4Ι | absolute value x-4 |
5√-32x³°y²° index of square root of -32 x to the power of 30 and x to the power of 20 | -2x⁶y⁴ | -2 * -2 * -2 * -2 *-2 = -32 x³°= 30 divided by 5 is 6 y²°= 20 divided by 5 is 4 |
-√4 negative square root of 4 | -2 | -2 * -2 = 4 |
3√-729 index of 3 square root of negative 729 | -9 | -9 * -9 * -9= 729 |
√-16 square root of negative 16 | not a real number | no real number is the √-16 |
f(x)= 3√x-14 find for f(13) f(x)= index 3 square root of x -14 | 3√-1 | 3√13-14 = -1 3√-1 |
√x⁶/81y square root of x⁶ over 81y | x³/9y | (x³)² = x⁶ 9 * 9 = 81 |
-4√1296 negative index of 4 square root of 1296 | -6 | -6 * -6 * -6 * -6 = 1296 |
3√(-8)³ index of 3 sqaure root of (-8)³ | -8 | index of 3 √-8 cubed is -8 |
√529 square root of 529 | 23 | 23x23=529 |