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Quadratic and graphs
Question | Answer |
---|---|
Whats the vertex of y=-2(x+3)^2+5 | Move left 3 and up 5 so vertex is (-3,5) |
What is axis of symmetry for vertex (3,6) | x=3 |
Whats vertex of y=-5x^2 | vertex is (0,0) |
whats vertex of f(x)=2(x-5/3)^2-1 | vertex is (5/3,-1) |
find vertex and direction of parabola y=x^2+6x+8 | opens upward because positive and vertex (-3,-1) after completing the square and turning into quadratic equation. |
find vertex y=x^2+7 | (0,7) |
which direction graph open y=-5(x+3)-2 | a=-5 which is negative so graph opens downward |
find axis of symmetry for y=-2(x+5)-1 | vertex (-5,-1) so x=-5 |
whats vertex y= -2/4(x+8/9)-8 | vertex (-8/9,-8) |