Rational Exponents Word Scramble
|
Embed Code - If you would like this activity on your web page, copy the script below and paste it into your web page.
Normal Size Small Size show me how
Normal Size Small Size show me how
Question | Answer |
Suppose X=7^(1/3). What would X^3=7^(1/3) be? | X=7^1 or 7 |
If X^3 = 7. Then X = the cubed root of 7. This means that the cubed root of 7 is = to | Cube root of 7 = 7^(1/3) |
4^(3/2) = | (Square root of 4) ^ 3. = (2)^3 = 8 |
25^(3/2) = | (sqrt of 25)^ 3 = (5)^3 = 125 |
4^(-4/2) = | 1/4^(4/2) = 1/ sqrt of 4 ^4 = 1/2^4 = 1/16 |
16^(-5/4) = | 1/16(5/4) = 1/ fourth root of 16 ^ 5 = 1/2^5 = 1/32 |
A^(2/2) Multiplied by A^(8/2) = | A^(8/2) = A^4 |
A^0 = | 1. A cannot equal 0 |
A^(-n) = | 1/A^(N) = A cannot equal 0 |
(The fourth root of x)^2 = | X^(2/4)= X^(1/2)= Sqrt of X. |
The 6th root of 25 = | 25^(1/6) = (5^2)^1/6 = (5)^2/6 = (5)^1/3 = Cubed root of 5. |
Created by:
Skymarie
Popular Math sets