Solving systems of linear equations by graphing and substitution
Quiz yourself by thinking what should be in
each of the black spaces below before clicking
on it to display the answer.
Help!
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Determine which ordered pair is a solution x+y=8 3x+2y=21 a- (2,4) b- (5,3) | b (5,3)
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Determine which ordered pair is a solution 3x-y=5 x+2y=11 a- (3, 4) b- (0, -5) | a (3, 4)
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Determine which ordered pair is a solution 2x+y=5 x+3y=5 a- (5, 0) b- (2, 1) | b (2, 1)
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Determine the number of solutions of a system 4x+y=24 x+2y=2 | The system has one solution it is intersecting lines.
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Determine the number of solutions of a system 2x+y=0 2y=x-4x | The system has no solution and is parallel lines.
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Use the substitution method to solve the system x+y=3 x=2y 2y+y=3 combine like terms 3y=3 divide both sides by 3 y=1 use y=1 in x=2y equation x=2(1) x=2 | (2, 1)
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Use the substitution method to solve the system x+y=6 y=-3x x+(-3x)=6 combine like terms -2x=6 divide both sides by -2 x=-3 substitute x=-3 into y=-3x equation y=-3(-3) y=9 | (-3, 9)
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Solve the system by graphing x+y=4 x-y=2 | x+y=4
substitute 0 for x
0+y=4
(0, 4)
substitute 0 for y
x+0=4
(4,0)
x-y=2
substitute 0 for x
0-y=2
(0,-2)
substitute 0 for y
x-0=2
(2,0)
The graph would intersect at (3,1)
(I am unable to put a graph in the flash cards sorry)
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Solve the system by graphing x+y=6 -x+y=-6 | x+y=6
substitute 0 for x
0=y=6
(0,6)
substitute 0 for y
x+0=6
(6,0)
-x+y=-6
substitute 0 for x
-0+y=-6
(0,-6)
substitute 0 for y
-x+0=-6
(6,0)
The graph would intersect at (6,0)
( I am unable to put a graph into the flash cards sorry)
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Solve by substitution y=3x+1 4y-8x=12 | 4y-8x=12 put y=3x+1 into the first equation
4(3x+1)-8x=12 distribute
12x+4-8x=12 combine like terms
4x+4=12 subtract 4 from both sides
4x=8 divide both sides by 4
x=2
put x=2 into y=3x+1
y=3(2)+1 distribute
y=6+1
y=7
(2,7)
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Created by:
michellewright85
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