Midsegments, bisectors, and points of concurrency.
Quiz yourself by thinking what should be in
each of the black spaces below before clicking
on it to display the answer.
Help!
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| A midsegment connects the ___ of 2 sides on a ___. | midpoints; triangle
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| Midsegment theorem- the midsegment of a triangle is parallel to the __ side and __ its length. | 3rd; 1/2
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| Theorem 5.2- If a point is on the perp. bisector of a segment, then it is ____ from the ___ of the segments. | equidistant; enpoints
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| Theorem 5.3- If a point is equidistant from the ___ of a segment, then it is on the ____ ____ of the segment. | endpoints; perpendicular bisector
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| Theorem 5.4- If a point is on the ____ of an ____, then the point is ____ from the sides of the angle. | bisector; angle; equidistant
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| Theorem 5.5- If a point in the ____ of an angle is ____ from the sides of the angle, then the point is on the ____ ____. | interior; equidistant; angle bisector
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| A point on the perp. bisector of a segment is | Equidistant to the endpoints
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| A point on an angle bisector is | Equidistant to the sides of the angle
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| Slope formula | Y2 - Y1 over X2 - X1
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| How to find a midpoint | m= (X1+X2 over 2, Y1+Y2 over 2)
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| Circumcenter is formed by | Perpendicular bisectors
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| A circumcenter is the | Center of the circle outside the triangle
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| Incenter is formed by | Angle bisectors
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| An incenter is the | Center of the circle inside the triangle
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| Centroid is formed by | Medians
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| A centroid is | 2/3 (2:1) the distance from vertex to midpoint
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| Orthocenter is formed by | Altitudes
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| An orthocenter has | No mathematical relationship
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| How to find circumcenter: | Midpoint to perpendicular bisector
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| How to find incenter | Vertex to side (does not have to be midpoint)
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| How to find centroid | Vertex to midpoint
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| How to find orthocenter | Vertex to perpendicular side, forming a right angle
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Created by:
mma129
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