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Physics Finals Help

Description:Need to study for Physics? Here are some questions to help you out!!!
Category: Physics
Created by: Tycheeman610 on 2006-01-18
Stack ID:32047

 
 
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SI units of length,mass, and time. The meter(m), the kilogram(kg), and the second(s), respectively.Liter(L). A volume of 1000mL, or 1000 cm. cubed. To a good approximation, a liter of water has a mass of 1kg. Dimensional analysis and/or unit analysis. Either can be used to determine if an equation has the correct form. Unit analysis can be used to find the unit of a quantity. Significant figures(digits). The digits that are known with certainty, plus one digit that is uncertain,in a measured value. Problem Solving. Problems should be worked using a consistent procedure. Order-of-magnitude calculations may be done when only an estimated value is desires. Density(row). The mass per unit volume of an object or substance, which is a measure of the compactness of the material it contains. p=m/v (mass/volume)Chapter 2. Motion involves a change of position; it can be described in terms of the distance moved(a scalar) or the displacement(a vector). A scalar quantity has magnitude(value and units)only; a vector quantity has magnitude and direction. Speed(a scalar) is the time rate of change of position:average speed=distance traveled/total time to travel that distance or average s=d/change in t=d/t2-t1. Average velocity(a vector) is the displacement divided by the total travel time: average velocity=displacment/total travel time or average v=change in x/change in t or x=x original+average velocity t. Instantaneous velocity(a vector)describes how fast something is moving and in what direction at a particular instant of time. Acceleration is the time rate of change of velocity and hence is a vector quantity: average acceleration=change in velocity/time to make the change.The kinematic equations for constant acceleration:average v=v+original v/2 v=original v=at x=original x+1/2(v+original v)t x=original x+original vt+1/2 atsquared v squared=v original squared+2a9x-original x). An object in free fall has a constant acceleration of magnitude g=9.80 m/s squared9acceleration due to gravity) near the surface of the Earth. Expressing a=-g in the kinematic equations for constant acceleration in the y-direction yields the following:v=original v-gt y=original y+1/2(v+original v)t y=original y+originalvt-1/2gtsquared v squared=voriginal squared-2g9y-yoriginal)
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