Question | Answer |
Find f(x) by finding three points on the line f(x)=2^x. | Plug in some points from a graph. Remember to correctly plot points on graph and connect the points.
X: -2 , 0 , 2
f(x): (1/4) , 1 , 4 |
Find y for the exponential function (1/2)^x. | Plug in some points from a graph.
X: -1 , 0 , 1
Y: 2 , 1 , (1/2) |
Find 4 points on the line of the exponential function f(x)=3^x+2. | Plug in plots from graph. Choose smaller numbers so you can plot the points easier.
X: -3 , -2 , -1 , 0
f(x): (1/3) , 1 , 3 , 9 |
Solve for x.
2^x=16 | Change base of 16 so that it matches 2.
1. 2^x=2^4
2. x=4 |
Solve for x.
9^x=27 | Change base of 27 so that it matches 9. Both bases are powers of 3.
1. (3^2)^x=3^3
2. Solve for x.
- 2^x=3
- (2^x)/2=3/2
- x=3/2 |
Find the amount owed at the end of 5 years if $1600 is loaned at a rate of %9 compounded monthly. | P= $1600
r= 0.09
n= 12
t= 5
Plug in the values into the equation.
A= $2505.09 |
A type of uranium has daily radioactive decay of 0.4%. If 40 pounds of this uranium is available today, find how much will still remain after 40 days.
Use y=40(2.7)^-0.004t | t= 40
Plug in t value.
y= 34.1 |
The equation y=84,943(1.095)^x models the number of college students who study abroad each year from 1995 through 2006. In the equation, x represents the number of years after 1995. Find the # of students studying abroad in (a) 2001 and (b) 2023. | Plug in x for the # of years after 1995.
(a) 84,943(1.095)^6=146,424.
(b) 84,943(1.095)^28=1,078,259 |
The equation y=114.65(1.114)^x gives the number of cellular phone users y (in millions) in a country for the years 2002 through 2009. In this equation, x=1 represents 2003. Find out how many users there will be in 2012. | Plug in x for the # of years up to 2012.
114.65(1.114)^10=337.5 |
Solve for x.
4^x+3=8^x | 1. (2^2)^x+3=(2^3)^x
2. (2x+6)-2x=3x-2x
3. 6=x |
Find f(x) by finding four points on the line f(x)3^x. | X: -2 , -1 , 3 ,2
f(x): (1/9) , (1/3) , 27 , 9 |