Question | Answer |
A circle's center is found at (3,4) and its radius is 2. Use this information and write the equation in standard form. | (x-3)^2+(y-4)^2=4 |
A circle's center is (0,-3) and its radius is 4. With the given information, write the equation of the circle. | (x-0)^2+(y+3)^2=16
OR
x^2+(y+3)^2=16 |
The equation for a circle is:
(x-2)^2+(y+3)^2=36
Find its center and radius. | Center=(2,-3)
Radius=6 |
The equation for a circle is:
x^2+y^2+4y=0
Find its center and radius. | Center=(0,-2)
Radius=2 |
Graph this equation:
(x-3)^2+y^2=49 | Center=(3,0)
Radius=7
points around center=(3,7),(3,-7),(-4,0),(10,0) |
Graph this equation:
x^2+y^2+2x-4y=11 | Center=(-1,2)
Radius=4
Points around center:(3,2),(-1,-2),(-5,2),(-1,6) |
Find the Center and the Radius of the circle, and then graph the circle.
(x-2)^2+(y+6)^2=9 | Center=(2,-6)
Radius=3
Points around center=(2,-9),(2,-3),(-1,-6),(5,-6) |
A circle's center is (4,5) and its radius is √11. Use this information to write the equation of the circle. | (x-4)^2+(y-5)^2=11 |
The equation for a circle is
x^2+(y+8)^2=18
Find the Center and the Radius. | Center=(0,-8)
Radius=√18 |
A circle's center is (-3,-7) and its radius is 9. Use this information to write the equation for this circle. | (x+3)^2+(y+7)^2=81 |