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Solving Quadratic Equations by the Quadratic Functions

Quiz yourself by thinking what should be in each of the black spaces below before clicking on it to display the answer.
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Question
Answer
solve by using quadratic formula x^2+3x+2=0   x= 1 or x= -2  
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solve by using quadratic formula (x+3)(x+2)=2   x= -1 or x= - 4  
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How many solution(s) will a negative discriminant have?   two complex but not real solutions  
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If the discriminant is positive how many solution(s) will it have?   two real solutions  
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If the discriminant is zero how many solutions will it have?   one real solution  
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a=1 b=3 c=4 use a, b, and c to find the discriminant then determine how many solution(s) it will have   -13, negative= two complex but not real solutions  
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a=2 b=20 c=1 use a, b, and c to find the discriminant, then determine how many solution(s) it will have   12, positive= two real solutions  
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use quadratic formula to solve (x+6)(x-1)=-2   x=-5+/- square root 41 all over 2  
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a=1 b=4 c=1 use a, b, and c to find the discriminant then determine how many solution(s) it will have.   x=0, zero= one real solution  
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2/3x^2+4/3x+1/3=0   x= -1+/- 1/2 sq root 2  
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Created by: lindsey94
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